Ken <tyl### [at] pacbellnet> wrote:
: That's no good because then you would fall off the edge of the world. Duh !

  But that would make a really good animation!

-- 
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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But it's impossible to move beyond the sky_sphere because it's infinite. It's
merely rendered as a sor of "backdrop" to the scene, the same regardless of
camera position. Kind of like those skies in Doom and Quake that don't appear
to get closer as you move.

Of course, that doesn't mean there's nothing else there... Suppose we live in
a three-dimensional universe that's like a "slice" of a four-dimensional one.
There's a whole nother dimension that we can't possibly get to.

Nieminen Juha wrote:

> Remco de Korte <rem### [at] xs4allnl> wrote:
> : Another interesting question might be: what's BEHIND a sky_sphere (or a
> : background).
>
>   That certainly is an interesting question. Perhaps if you move the
> camera very very very very far away from the origin, you will reach the
> border of the sky_sphere...
>
> --
> main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
> ):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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Larry Fontaine wrote:
> 
> But it's impossible to move beyond the sky_sphere because it's infinite. It's
> merely rendered as a sor of "backdrop" to the scene, the same regardless of
> camera position. Kind of like those skies in Doom and Quake that don't appear
> to get closer as you move.
> 
> Of course, that doesn't mean there's nothing else there... Suppose we live in
> a three-dimensional universe that's like a "slice" of a four-dimensional one.
> There's a whole nother dimension that we can't possibly get to.

  I think that you will find that the people in this thread know all about
how the sky sphere is implemented. The sky sphere is not even really infinite.
It exsists everywhere something else isn't. More specificaly everywhere there
is no object the skysphere fills in the unused pixels. A fancy fog of sorts.

We were just having fun...

-- 
Ken Tyler

See my 850+ Povray and 3D Rendering and Raytracing Links at:
http://home.pacbell.net/tylereng/index.html

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Ken <tyl### [at] pacbellnet> wrote:
:   I think that you will find that the people in this thread know all about
: how the sky sphere is implemented. The sky sphere is not even really infinite.

  Moreover: The sky sphere is actually a sphere of radius 1 with its
center at the camera location. The differences between a regular sphere and
the sky sphere are, AFAIK:
  1) Ray-object intersection tests are done with the sky sphere only if the
ray in question doesn't hit any other object. If the ray hits another object,
the sky sphere is completely ignored.
  2) The sky sphere is not shaded, that is, no lighting calculations are done
to the sky sphere but the color of the intersection point is taken as is.
  3) You can only apply a pigment to the sky sphere. This is a direct
consecuence of the previous feature (finish and normal are only applicable
when calculating shading; also reflection is not applicable since we are
handling a sphere of radius 1, which probably doesn't surround the whole
scene).

: We were just having fun...

  Yes, pov-humor, you know... Only povrayers understand pov-humor... :)

-- 
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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I have a question for the hardcore povrayers (I can only guess the correct
answer, but I'm not sure about it):

  The sky sphere is a sphere of radius 1 around the camera, as I described
in the previous article.
  Now suppose that the camera is at the origin and a ray is shot from it in
the z direction and it hits a reflective object at <0,0,2>. The reflected
ray is shot in the x direction (ie. it made a 90 degrees turn). This
reflected ray doesn't hit anything else.
  Since it doesn't hit anything else, it is tested against the sky sphere.
But since the sky sphere is a sphere of radius 1 at the origin, this ray
doesn't (?) hit it.
  How is this solved?

-- 
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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On 3 Sep 1999 07:26:01 -0400, Nieminen Juha wrote:
>  I have a question for the hardcore povrayers (I can only guess the correct
>answer, but I'm not sure about it):
>
>  The sky sphere is a sphere of radius 1 around the camera, as I described
>in the previous article.

Not true.  The sky sphere is a bit of code that takes a ray that didn't 
hit anything else and colors it based on its direction, according to the
documentation.  That fact invalidates the rest of your question. :)

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(Speculation)
I suspect the sky_spere is not exactly represented as an unit sphere around the
camera, but around the start of a ray (camera, reflected, refracted...) More
exactly, the returned value would be that of the pigment 1 unit away from the
origin, in the (relative) direction of the ray. Since only the direction is
important, this would give the desired result.

Margus

Nieminen Juha wrote:
> 
>   I have a question for the hardcore povrayers (I can only guess the correct
> answer, but I'm not sure about it):
> 
>   The sky sphere is a sphere of radius 1 around the camera, as I described
> in the previous article.
>   Now suppose that the camera is at the origin and a ray is shot from it in
> the z direction and it hits a reflective object at <0,0,2>. The reflected
> ray is shot in the x direction (ie. it made a 90 degrees turn). This
> reflected ray doesn't hit anything else.
>   Since it doesn't hit anything else, it is tested against the sky sphere.
> But since the sky sphere is a sphere of radius 1 at the origin, this ray
> doesn't (?) hit it.
>   How is this solved?
> 
> --
> main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
> ):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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