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Given a vector <a,b,c>, how would I go about calculating a new vector within
x degrees of the original vector?
i.e. given a cone:
cone{<1,1,1>, 25, <0,0,0>,0}
a random vector within 25 degrees would lie within the cone's radius.
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OK, given the vector:
V: |------------>
A B
I'd rotate first this vector V around
any axis, that is perpendicular to V
and goes through A. Here you can use
any angle between 0 and 25 degree.
Afterwards you rotate this new vector
around the axis of the original vector V
by any random angle ...
This should work, but would merely give
an equal distribution of the results ...
So if this should be your goal, there is
probably a better method.
BTW: Are you sure, that your given Cone
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"Jan Walzer" <jan### [at] lzer net> wrote in message news:3cbdee24@news.povray.org...
>
> OK, given the vector:
>
>
> V: |------------>
> A B
>
> I'd rotate first this vector V around
> any axis, that is perpendicular to V
> and goes through A. Here you can use
> any angle between 0 and 25 degree.
> Afterwards you rotate this new vector
> around the axis of the original vector V
> by any random angle ...
Makes sense - god, I'm dumb.
> BTW: Are you sure, that your given Cone
Ah - of course it doesn't. What was I thinking? Got it into my head the 4th
param was the angle, not the radius.
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"Tom Melly" <tom### [at] tomandlucouk> wrote in message
news:3cbde9a1@news.povray.org...
> cone{<1,1,1>, 25, <0,0,0>,0}
>
> a random vector within 25 degrees would lie within the cone's radius.
>
Which, of course, is nonsense....
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Tom Melly wrote:
>
> Given a vector <a,b,c>, how would I go about calculating a new vector
> within x degrees of the original vector?
Depends on what kind of distribution you want. If the vectors in the
cone are equally likely, the method is different from, say, having the
ones around the center be more likely than the rest.
Regards,
John
--
Rusty is rendering!
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