

"Bald Eagle" <cre### [at] netscapenet> wrote:
Hang on  slight confusion:
> I'm guessing that in order to do something like plot a gradient field, I need to
> do something like evaluate the ...
partial derivatives of W = F(x,y,z)
> separately for x, y,
> and z in order to get a vector for the actual gradient?
>
> Then if I wanted to show the gradient of a curve, I'd
draw a cylinder from the origin to Gradient * S(scalar) and translate to P
> And the normal
is the gradient, and
> the dot product of
> the [normalized?] gradient vector and the
derivative is zero, since they are perpendicular.
> Do I
[finally]
>have this all correct?
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