"Bald Eagle" <cre### [at] netscapenet> wrote:

Hang on - slight confusion:

> I'm guessing that in order to do something like plot a gradient field, I need to
> do something like evaluate the ...

partial derivatives of W = F(x,y,z)

> separately for x, y,
> and z in order to get a vector for the actual gradient?
>
> Then if I wanted to show the gradient of a curve, I'd

draw a cylinder from the origin to Gradient * S(scalar) and translate to P

> And the normal

is the gradient, and

> the dot product of

> the [normalized?] gradient vector and the

derivative is zero, since they are perpendicular.

> Do I

[finally]

>have this all correct?

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