In article <38E3ACD4.9A9E063B@online.no>, tor### [at] hotmailcom wrote:

> Warp wrote:
> 
> >   You have to remember that a macro is _not_ a function. A macro is a
> > substitution string. The body if the macro is inserted in the place of
> > the call as-is.
> 
> Hmmm...
> If that is true, then why does this not work?

Er, well...it should work.
I tried some other combinations, putting the brackets outside the macro, 
enclosing each value with parenthesis...it still doesn't work. When I 
put a #debug statement in the macro, I found the macro is never called. 
Maybe you should compose a bug report. This looks like a real bug.

-- 
Christopher James Huff - Personal e-mail: chr### [at] yahoocom
TAG(Technical Assistance Group) e-mail: chr### [at] tagpovrayorg
Web page: http://chrishuff.dhs.org/

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