In article <387EA67E.7CE91E84@faricy.net>, David Fontaine 
<dav### [at] faricynet> wrote:

> What I think POV *should* do is not include these areas in the graph. Say 
> I
> want to graph a hemisphere on my TI-89, I do x^2+y^2+z^2=1, 
> z^2=-x^2-y^2+1,
> z=sqrt(1-x^2-y^2), and graph it and it gives me my hemisphere, and the 
> area
> *outside* the hemisphere is ignored (not rendered) because it is 
> sqrt(neg).
> Because if people want it to work the other way they can always just make
> it sqrt(abs(x)) instead of sqrt(x).

I think this might be difficult to do, because the isosurface is solved 
by sampling the function at different points. I don't see how it could 
be done.
Then again, it is after midnight now, it is probably just that I am 
tired and not thinking straight.

-- 
Chris Huff
e-mail: chr### [at] yahoocom
Web page: http://chrishuff.dhs.org/

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