In article <3DF1C3CD.A9BA456F@hotmail.com>,
 Dan Johnson <zap### [at] hotmailcom> wrote:

> If my thinking is correct that can be done such that each vertex is
> exactly on the surface of the sphere. 

You are correct (assuming no uneven scaling or shearing), but I think a 
box would be a better choice. A sphere doesn't fit a tetrahedron that 
closely, a box isn't much if at all better but is faster to test.

-- 
Christopher James Huff <cja### [at] earthlinknet>
http://home.earthlink.net/~cjameshuff/
POV-Ray TAG: chr### [at] tagpovrayorg
http://tag.povray.org/

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