|
|
On Fri, 21 Jan 2000 15:53:04 -0600, David Fontaine <dav### [at] faricynet>
wrote:
>So is the integral of sin(x) the area between the x-axis and sin(x) between x=0
>and x=x?
The integral of sin(x) (with respect to x :) ) is -cos(x). This is the
general form. In order to evaluate it for a particular range of x, or
in your case to find the area enclosed by the sine function and some
segment of the +x axis, you need to calculate the integral for that
range. Say the range is (a,b) then the integral evaluates to
-cos(b)-(-cos(a)) or cos(a)-cos(b). Of course this may give 0 as a
result and even though it represents an area this should not surprise
you because the part of the curve below the x axis is weighted
negatively.
Peter Popov
pet### [at] usanet
ICQ: 15002700
Post a reply to this message
|
|