It is known that increasing the max_gradiant makes an isosurface go 
slower. It is also known that if you just divide the result of the 
function you're drawing, it lowers the max_gradiant, but it won't render 
any faster.

I was wondering... if I (say) take the square root, that makes the high 
values less high, while leaving zero unchanged. (I'm assuming 
threshold=0 here.) Would that make the thing go any faster? Would the 
increase in speed overcome the extra computation needed for the sqrt() call?

Andrew @ home.

Post a reply to this message