The isosurface defined by a function f is equivalent to the isosurface 
defined by pow(f,2) if threshold it 0, so you should define your sphere 
more simply with the functions.inc function f_sphere (x,y,z,1) and you 
will see it.

JC

Peter Lang wrote:
> Hello,
> I am just trying to understand the function of isosurface .
> As I understand the surface of an object is just there where the function
> get zero
> So I get a simple sphere with the following:
> isosurface {  function { pow(x,2) + pow(y,2) + pow(z,2) - 1   }
> 
> But I thougt if I take the funktion to the sqare there should be no
> difference
> because the square of zero is still zero
> But
> isosurface {  function { pow( (pow(x,2) + pow(y,2) + pow(z,2) - 1) ,2)  }
> gives no object.
> please tell me why
> 
> peter
> 
>

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