> I don't know exponential functions very well, but I agree that it
> shouldn't be that difficult to get smooth blobs, and that it would only
> require the individual blob components to use functions whose second
> derivatives match up.


Not too difficult; you just have to find a polynomial such that

f(0) = 0
f(1) = 1
f(0)' = 0
f(1)' = 0
f(0)" = 0
f(1)" = 0

But it will end up being a pretty high order polynomial, which introduces
slowness and innacuracy.

 - Slime
[ http://www.slimeland.com/ ]

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