Andrew Coppin wrote:
> 
> I seldom cease to be humbled by the skill of the folks on this news

> 

I just see right now that my result is a bit more complicated than it needs 
to be.. you can get rid of the exp/ln if you put k = -ln(p) back into the 
equation:

 v(T + deltaT) = v(T) * exp(-k*deltaT) = v(T) * exp(ln(p)*deltaT) 
               = v(T) * p^deltaT

That means, e.g. with p = 0.3 and deltaT = 0.01 you get

 v(T+0.01) = v(T) * 0.3^0.01 = v(T) * 0.98803

But the calculation serves as justification for this formula (You wouldn't 
want use something you didn't prove ;) )

- Micha

BTW: You should really get into differential equations... it's one of the 
most interesting things in math.

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