"Peter Popov" wrote:
> I still don't have a clue how to proceed once I have the
> screen coordinates of the vertices. I have to start with
> a square and scale, rotate & tilt it to its deformed shape.
> It is possible since a cube face in orthographic projection
> will always be a parallelogram, but how?

Well, you could start with finding the width and height of the
input-face-parallelogram, and scale the output-face so it has the same
proportions. The you can find the angle of one of the corners in the
input-face and tilt the output-face so it has the same angle in the corner.
Then find out how much you must rotate the output-face to match the
input-face. Finally translate it if that's necessary.

Hope that helps. If you need more details, I'll need more details first...
:)

Rune
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