Serge LAROCQUE wrote:
>Ok, so now, calculate all the points of intersection,
>store in a list somehow. Check them for being
>interior points with the inequality
>(x-xi)^2+ (y-yi)^2 < 1 for each circle, where (xi,yi)
>is the centre of circle i. Discard any points that
>satisfy the the inequality. You are left with all the
>exterior points. Calculate their distance from P and
>pick the nearest one.

Yes, I too have found that that's the only way.
Now I just need to know how to calculate all the
points of intersection. How do I do that?

Greetings,

Rune

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