> If your normal vector is <a,b,c> and the position of the point is <x,y,z>,
> you should just have to test a*x+b*y+c*z, if it's positive, the point is in
> front of the plane, if it's negative, the point is behind the plane, and if
> it's zero, the point lies on the plane.

Thanks! Actually I got it from by brother just a couple of minutes ago, I can't
believe it was so simple...

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