On Tue, 23 May 2000 01:58:30 +0300, Margus Ramst <mar### [at] peakeduee>
wrote:

>> This is not what I had in mind. This only scales the local coordinate
>> axes but does not change the angle between them, as skewing does
>
>This transform does indeed skew the object, but you'd have to use a bit of trig
>to get the skewing along a specific axis.

I see, so shearing comes down to scaling along (an) axe(i)s which are
(is) not perpendicular to the local axes. Am I right in guessing that?
If so, thanks for clearing it up for me! If not, I'd be thankful if
you cleared it up for me <grin>


Peter Popov ICQ : 15002700
Personal e-mail : pet### [at] usanet
TAG      e-mail : pet### [at] tagpovrayorg

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