Le_Forgeron <lef### [at] freefr> wrote:
> Le 13/11/2012 07:04, Stephen a écrit :
> >
> > I did some quick calculations and knowing that the centripetal force is
> > equal to minus the angular velocity squared times the radius times the
> > mass (F = -W^2*r*m).
> > If the torus was revolving around its centre once in 24 hours. On the
> > inner surface the force would be about 0.508g and on the outside surface
> > 0.529g. If the period was 12 hours the forces would be 2.03g and 2.116g
> > respectively. Note the sleight of hand going from force to acceleration ;-)
>
>
> There is more than just a delta in the centripetal force. (on the outer
> circle, it is opposite direction of gravity (like on earth); on the
> inner circle, it should be the same direction as local gravity (but the
> local gravity is diminished due to the point being between "two massive
> parts"

Sorry, I hab a told. :-)
I thought that was implicit when I said centripetal and minus.
It is interesting what happens to the vectors at the edge of the torus.

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