"Nekar Xenos" <nek### [at] gmailcom> wrote:
> Hmm. There are 2 bricks above and 2 bricks below each brick and one on
> each side = 6 bricks. I'll have to make a larger variety of bricks!
>
> -Nekar Xenos-

Not necessarily. See the attached (plagerized) image. With three brick types,
it's possible that no brick would be directly adjacent to another brick of the
same type. There's not a whole lot of randomness in this case, though!

Regards,
Dave Blandston

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