Warp <war### [at] tagpovrayorg> wrote:
>
>   The whole idea of the given algorithm (ie. get a random point evenly
> distributed on a disc and then parallel-project it to a hemisphere
> correspondent to that disc) is that you don't need any trigonometry
> anymore, and the points will be automatically distributed on the
> hemisphere according to the cosine function. (Square root of multiplications
> is equivalent to sin/cos.)

Yeah, I know that. That's all the point I'm trying to make. Well, except that I
wasn't aware that it even gets you rid of any trigonometrics at all.

Post a reply to this message