|
 |
stbenge <stb### [at] hotmail com> wrote:
> Ray Bellis wrote:
> > stbenge wrote:
> >> Hi everyone,
> >>
> >> Today I figured out a couple of mathematical expressions to find the
> >> number of bricks for any given 2d or 3d pyramid. I had previously
> >> figured out the 2d version, but the equation was a bloated
> >> monstrosity. The new one is much simpler!
> >
> > http://pirate.shu.edu/~wachsmut/ira/infinity/answers/sm_sq_cb.html
> >
> > 2D pyramid = 1 + 2 + 3 + .. + n
> > = n * (n + 1) / 2
> >
> > 3D pyramid = 1 + 2^2 + 3^2 + .. + n^2
> > = n * (n + 1) * (2n + 1) / 6
>
> Yeah well, like I said, it was fun to come up with this independently. I
> wonder if anyone else has used a similar geometric approach?
>
> Sam
you cant just leave it like that.
4D pyramid = 1 + 2^3 + 3^3 + .. + n^3
Post a reply to this message
|
|
