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>>>> That's also why, even if complex cannot be extended in 3D, they can in
>>>> 4D. (look at quaternion...)
>>>
>>> No. Quaternions do not form a field. Neither do the hypercomplex
>>> numbers, nor any of the other 4D generalisations.
>>>
>>
>> That's irreverent to Le_Forgeron's point. The application of the hairy
>> ball theorem here does not depend on the numbers forming a field.
>
> I should clarify, I took the fact that the extension wouldn't be a field
> to be implicit in Le_Forgeron's point, since the Hairy ball theorem's
> use doesn't depend on the numbers forming a field. Not saying your
> reading was technically incorrect.
By "extend the complex numbers", I implicitly meant to extend it to make
a larger /field/. Apparently that is impossible. There are of course
several ways you can extend them if you don't mind the result failing to
be a field...
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On 5/8/2012 8:23 AM, Invisible wrote:
>> I should clarify, I took the fact that the extension wouldn't be a field
>> to be implicit in Le_Forgeron's point, since the Hairy ball theorem's
>> use doesn't depend on the numbers forming a field. Not saying your
>> reading was technically incorrect.
>
> By "extend the complex numbers", I implicitly meant to extend it to make
> a larger /field/. Apparently that is impossible. There are of course
> several ways you can extend them if you don't mind the result failing to
> be a field...
This is certainly true, but your options are more limited in 3d than in
4d. I was just assuming that Le_Forgeron was already well aware that
quaternions aren't a field. Operating under this assumption I took his
point to be that your options for extending the complex numbers to 3d
are more limited then when extending them to 4d, even though obviously
neither extension will result in a field.
Your interpretation of Le_Forgeron is of course also consistent with
what he posted. However I'm confused how you reconcile this "any
extension must be a field" view with your original post. In the initial
post you say:
"Question: Why can't you extend the complex numbers to 3D space?
Answer: Because the hairy ball theorem says so."
But that seems a pretty weak explanation of why such an extension isn't
possible if you're insisting that the extension be a field. After all
such an extension isn't possible to 4d, even though the hairy ball
theorem *doesn't* apply in that case. If you're going to take this view
why bother with the hairy ball theorem at all? You can prove more by
other means.
If, on the other hand, you allow the extension to not form a field, then
it makes more sense why you'd use the hairy ball theorem, as it helps to
explain why the quaternions are possible in 4d but not 3d. Not saying
your view is wrong in a technical sense... it just seems a little
hodge-podge to me. Perhaps I am missing something?
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Invisible <voi### [at] dev null> wrote:
> No. Quaternions do not form a field. Neither do the hypercomplex
> numbers, nor any of the other 4D generalisations.
The reason is that it's not possible to make multiplication commutative
for them.
--
- Warp
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On 08/05/2012 06:23 PM, Warp wrote:
> Invisible<voi### [at] dev null> wrote:
>> No. Quaternions do not form a field. Neither do the hypercomplex
>> numbers, nor any of the other 4D generalisations.
>
> The reason is that it's not possible to make multiplication commutative
> for them.
The hypercomplex numbers possess commutative multiplication. What they
do /not/ possess is multiplicative inverses. (Not for all elements, anyway.)
In short, you can construct lots of 4D number systems, all of which fail
to be a field in a different way.
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On 08/05/2012 04:43 PM, Kevin Wampler wrote:
> "Question: Why can't you extend the complex numbers to 3D space?
>
> Answer: Because the hairy ball theorem says so."
>
> But that seems a pretty weak explanation of why such an extension isn't
> possible if you're insisting that the extension be a field. After all
> such an extension isn't possible to 4d, even though the hairy ball
> theorem *doesn't* apply in that case. If you're going to take this view
> why bother with the hairy ball theorem at all? You can prove more by
> other means.
OK, point taken.
It's just that the "other means" are usually incomprehensible, whereas
"you can't comb a sphere flat" is a pretty intuitive description of why
you can't do something.
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On 5/8/2012 7:34, Kevin Wampler wrote:
> On 5/7/2012 6:53 PM, Darren New wrote:
>>
>> I.e., you can do math on "the probability that X happens given that Y
>> happens" and deal with "and" and "or" and Bayesian probabilities, using
>> either real numbers or complex numbers, but not 3D numbers.
>>
>
> Do you happen to remember the name of this theorem? I'm curious how fierce a
> devil is in the details.
I know where I read about it, I think. I'll try to check if it's actually
named when I find the book. :-)
--
Darren New, San Diego CA, USA (PST)
"Oh no! We're out of code juice!"
"Don't panic. There's beans and filters
in the cabinet."
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On 5/11/2012 9:43 AM, Darren New wrote:
>> Do you happen to remember the name of this theorem? I'm curious how
>> fierce a
>> devil is in the details.
>
> I know where I read about it, I think. I'll try to check if it's
> actually named when I find the book. :-)
>
If you have the name of the book and don't feel like looking for it
yourself, that'd probably be enough for me to go on.
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On 5/11/2012 11:07, Kevin Wampler wrote:
> If you have the name of the book and don't feel like looking for it
> yourself, that'd probably be enough for me to go on.
It was mentioned somewhere when I was reading about quantum physics, either
wikipedia or Feynman's QED or something. I can't really find it, but it's
basically the complex probability amplitude equations, and a mention that
you don't get the multiplcation/addition of probabilities working out to
(for example) always come out as "1" if you go higher than two dimensions.
--
Darren New, San Diego CA, USA (PST)
"Oh no! We're out of code juice!"
"Don't panic. There's beans and filters
in the cabinet."
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