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Hi
Happy new years !
I have a small problem
I written the following simple macro
#macro Foot(c1,c2,R,col)
cylinder {
C1
c2
R
pigment {color col}
}
#end
with such a call
#declare MyRedFoot = Foot(<0,0,0>,<0,10,0>,1,Red)
But i would like to calle
#declare MyRedFoot = Foot(<0,0,0>,h,1,Red)
where h is height of foot. Macro would be
#macro Foot(c1,h,R,col)
cylinder {
C1
<x.C1, y.C1 + h, z.C1>
R
pigment {color col}
}
but of course it doesn't work like i hope because i do not know x y and z
How to get x, y and z of C1 ?
Thanks a lot
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"Coucou" <dom### [at] neuffr> wrote:
......
> How to get x, y and z of C1 ?
You can write:
vdot(C1, x)
vdot(C1, y)
vdot(C1, z)
- or shorter:
C1.x
C1.y
C1.z
Also have a look here:
http://www.povray.org/documentation/view/3.6.1/229/#s02_02_01_04_03
"2.2.1.4.3 Operators"
(The last part of that section is about the dot operator.)
--
Tor Olav
http://subcube.com
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Tor Olav Kristensen <tor### [at] toberemovedgmailcom> wrote:
> "Coucou" <dom### [at] neuffr> wrote:
> ......
> > How to get x, y and z of C1 ?
> You can write:
> vdot(C1, x)
> vdot(C1, y)
> vdot(C1, z)
> - or shorter:
> C1.x
> C1.y
> C1.z
I hate to sound rude, but I really don't understand why give first a rather
contrived answer of "vdot(C1, x)" and then give the right answer "C1.x".
The dot product does produce the same result, but it's a needlessly
complicated solution, so I don't really understand why you even suggested it.
--
- Warp
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By the way:
I did not notice to which news group you had posted your question.
Your question belongs in the povray.newusers group:
http://news.povray.org/povray.newusers/
- not in the povray.news-submissions group.
Please read "Using The Groups" in the following post:
http://tinyurl.com/yj6btea
http://news.povray.org/povray.announce.frequently-asked-questions/thread/%3C3D4C20DA.40C33E49%40pacbell.net%3E/
--
Tor Olav
http://subcube.com
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Warp <war### [at] tagpovrayorg> wrote:
> Tor Olav Kristensen <tor### [at] toberemovedgmailcom> wrote:
> > "Coucou" <dom### [at] neuffr> wrote:
> > ......
> > > How to get x, y and z of C1 ?
>
> > You can write:
>
> > vdot(C1, x)
> > vdot(C1, y)
> > vdot(C1, z)
>
> > - or shorter:
>
> > C1.x
> > C1.y
> > C1.z
>
> I hate to sound rude, but I really don't understand why give first a rather
> contrived answer of "vdot(C1, x)" and then give the right answer "C1.x".
> The dot product does produce the same result, but it's a needlessly
> complicated solution, so I don't really understand why you even suggested it.
Ok, the documentation says that the dot operator is used to extract components
from vectors.
- But the reason that I wrote it that way, is because I like to think of the
"C1.x" form as a short form of the dot product between the C1 vector and the
basis vector x.
It wasn't my intention to confuse anyone.
(Several ASCII-coded texts/papers/posts about vector math use the "." as the
vector dot product operator.)
--
Tor Olav
http://subcube.com
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