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"Bald Eagle" <cre### [at] netscape net> wrote:
> "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> ... I would also like to figure out if there's a nice
> degrees-to-fractions-of-pi algorithm out there, and I could implement that.
> I'll probably just hard-code an array of text objects.
You can divide the angle by 180 and convert the resulting decimal number to a
fraction. Then you can use David Eppstein's "find rational approximation to
given real number" code as suggested in the first answer here:
https://stackoverflow.com/questions/95727/how-to-convert-floats-to-human-readable-fractions
>...
> Do you watch 3blue1brown's channel? It's - peaceful, and elegant, and
> mesmerizing. It's one of the best things to happen to math in a long while.
> :)
Yes, I've seen some of his videos. Very good =)
I'm looking forward to the rest of them.
--
Tor Olav
http://subcube.com
https://github.com/t-o-k
Post a reply to this message
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"Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> "Bald Eagle" <cre### [at] netscape net> wrote:
> > "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> > ... I would also like to figure out if there's a nice
> > degrees-to-fractions-of-pi algorithm out there, and I could implement that.
> > I'll probably just hard-code an array of text objects.
>
> You can divide the angle by 180 and convert the resulting decimal number to a
> fraction. Then you can use David Eppstein's "find rational approximation to
> given real number" code as suggested in the first answer here:
>
>
https://stackoverflow.com/questions/95727/how-to-convert-floats-to-human-readable-fractions
I tried at least 2 different ways to go about this, but I didn't have any
success and fell into some kind of trap in the recursion programming that
short-circuits things. It was a mess that I spent too many hours trying to
fix.
I have more application cases that I'd like to apply this sort of thing to, if
you give me a nudge in the proper direction.
Thanks,
- BW
Post a reply to this message
Attachments:
Download 'rationalapproximation.pov.txt' (7 KB)
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"Bald Eagle" <cre### [at] netscape net> wrote:
> "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> > "Bald Eagle" <cre### [at] netscape net> wrote:
> > > "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> > > ... I would also like to figure out if there's a nice
> > > degrees-to-fractions-of-pi algorithm out there, and I could implement that.
> > > I'll probably just hard-code an array of text objects.
> >
> > You can divide the angle by 180 and convert the resulting decimal number to a
> > fraction. Then you can use David Eppstein's "find rational approximation to
> > given real number" code as suggested in the first answer here:
> >
> >
https://stackoverflow.com/questions/95727/how-to-convert-floats-to-human-readable-fractions
>
>
> I tried at least 2 different ways to go about this, but I didn't have any
> success and fell into some kind of trap in the recursion programming that
> short-circuits things. It was a mess that I spent too many hours trying to
> fix.
>
> I have more application cases that I'd like to apply this sort of thing to, if
> you give me a nudge in the proper direction.
Hi
As I know that you are very fond of Python, I'll nudge you to have a
look this code (which SEEMS to work ok):
# real_num: real number to approximate
# max_denom: maximum denominator allowed
def real_to_fraction(real_num, max_denom):
max_int = 2**31 - 1 # LONG_MAX == 0x7FFFFFFF in C
x = real_num
max_denom = int(max_denom)
m00 = int(1)
m01 = int(0)
m10 = int(0)
m11 = int(1)
# loop finding terms until denominator gets too big
ai = int(x)
while (m10*ai + m11 <= max_denom):
tmp = m00*ai + m01
m01 = int(m00)
m00 = int(tmp)
tmp = m10*ai + m11
m11 = int(m10)
m10 = int(tmp)
if (x == ai):
break # AF: division by zero
x = 1/(x - ai)
if (abs(x) > max_int):
break # AF: representation failure
ai = int(x)
# now remaining x is between 0 and 1/ai
# approximate as either 0 or 1/m where
# m is max that will fit in max_denom
# first try zero
error = real_num - m00/m10
print(f'{m00}/{m10}, error = {error}\n')
# then try other possibility
ai = int((max_denom - m11)/m10)
m00 = int(m00*ai + m01)
m10 = int(m10*ai + m11)
error = real_num - m00/m10
print(f'{m00}/{m10}, error = {error}\n')
Test run:
real_to_fraction(3.875, 100)
31/8, error = 0.0
376/97, error = -0.0012886597938144284
The type long in C is the same as the type signed long int.
So I put int() around every expression going into variables
of type long.
As you know, I don't like break statements in loops, so this
remains to be fixed.
In Python max_int should probably be chosen to be maxsize or
maxsize - 1 (after doing "from sys import maxsize").
--
Tor Olav
http://subcube.com
https://github.com/t-o-k
Post a reply to this message
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"Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
>...
> tmp = m00*ai + m01
> m01 = int(m00)
> m00 = int(tmp)
> tmp = m10*ai + m11
> m11 = int(m10)
> m10 = int(tmp)
>...
Sorry, that was not very Pythonic. I try again:
m00, m01 = int(m00*ai + m01), int(m00)
m10, m11 = int(m10*ai + m11), int(m10)
--
Tor Olav
http://subcube.com
https://github.com/t-o-k
Post a reply to this message
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"Bald Eagle" <cre### [at] netscape net> wrote:
> "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> > "Bald Eagle" <cre### [at] netscape net> wrote:
> > > "Tor Olav Kristensen" <tor### [at] TOBEREMOVEDgmail com> wrote:
> > > ... I would also like to figure out if there's a nice
> > > degrees-to-fractions-of-pi algorithm out there, and I could implement that.
> > > I'll probably just hard-code an array of text objects.
> >
> > You can divide the angle by 180 and convert the resulting decimal number to a
> > fraction. Then you can use David Eppstein's "find rational approximation to
> > given real number" code as suggested in the first answer here:
> >
> >
https://stackoverflow.com/questions/95727/how-to-convert-floats-to-human-readable-fractions
>
>
> I tried at least 2 different ways to go about this, but I didn't have any
> success and fell into some kind of trap in the recursion programming that
> short-circuits things. It was a mess that I spent too many hours trying to
> fix.
>
> I have more application cases that I'd like to apply this sort of thing to, if
> you give me a nudge in the proper direction.
I just had a look at you code and found that perhaps you are
misunderstanding what the value of this C expression is:
(ai = (long)x)
This is an assignment, where the value in X is converted to an
unsigned long int, then converted to the type of ai (which is
also an unsigned long int) and then stored in ai. The value of
the whole parenthesis expression is now equal to ai and can be
used in further calculations.
See this page:
https://stackoverflow.com/questions/9514569/what-does-an-assignment-return
In POV-Ray's SDL this expression:
(ai = x)
- is a comparison that is true when ai equals x and false otherwise.
So the value of the parenthesis expression is either 0 (for false)
or 1 (for true).
See "Relational expressions" (and the text right before) here:
https://wiki.povray.org/content/Reference:Numeric_Expressions
Also, you should call your macros with the second argument
(for the d parameter) greater than or equal to the greatest
denominator that you will accept. I.e. If you will accept
denominators up to 100, then pass 100 (not something small as
0.000001).
--
Tor Olav
http://subcube.com
https://github.com/t-o-k
Post a reply to this message
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