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Peter Popov wrote:
>
> <ake### [at] goteborgmailteliacom> wrote:
>
> >Hi.
> >
> >Does anyone know if it is possible to calculate the Mandelbrot set in 3D,
> >and if this is possible to render with POV?
> >
> >Regards,
>
> You're lucky, two minutes ago I was looking at Mark's post looking for
> the formula that he posted there so that I can give it to Warp for his
> fractal patch, so here I am with this thing in the clipboard:
You might find this interesting. This was just submitted to the links
collection and looks interesting at least for those interested in fractal
based programs.
***
Fractal Programs - A number of Win32 (fractal) programs by Terry Gintz,
one (FractalZPlot) being especially interesting because of the ability
to convert the z-buffer information of its 3d-fractal types to Wavefront
OBJ-format. These in turn can be converted by one of the many conversion
programs available to povray format for rendering of the 3D fractal object.
http://www-hs.iuta.u-bordeaux.fr/terry/
***
--
Ken Tyler - 1100+ Povray, Graphics, 3D Rendering, and Raytracing Links:
http://home.pacbell.net/tylereng/index.html http://www.povray.org/links/
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Peter Popov wrote:
> These are 2D M-Sets, Ken.
Ok fine ! Last time I try to help someone around here again.
--
Ken Tyler - 1200+ Povray, Graphics, 3D Rendering, and Raytracing Links:
http://home.pacbell.net/tylereng/index.html http://www.povray.org/links/
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Ken <tyl### [at] pacbellnet> writes:
> Peter Popov wrote:
>
> > These are 2D M-Sets, Ken.
>
> Ok fine ! Last time I try to help someone around here again.
I hope there is a smiley missing...
Thomas
--
http://thomas.willhalm.de/
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Peter Popov <pet### [at] usanet> wrote:
: #declare Rn = (R*R-I*I)+X;
: #declare In = (2*R*I-J*J)+Y;
: #declare Jn= (2*J*I+2*J*R)+Z;
Where does this formula come from? Is the formula for Jn just a randomly
chosen one?
What's the bailout value?
--
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/
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Thomas Willhalm <tho### [at] willhalmde> wrote in message
news:qqm### [at] goldachfmiuni-konstanzde...
> Ken <tyl### [at] pacbellnet> writes:
>
> > Peter Popov wrote:
> >
> > > These are 2D M-Sets, Ken.
> >
> > Ok fine ! Last time I try to help someone around here again.
>
> I hope there is a smiley missing...
Irony is such a difficult thing...
--
------------------------------------------------------------------------
+47 90 62 71 78 DoD#2101, NIC#015, Ducati M600, PJ#006, OGM#007
azo### [at] dodno, "Do one thing every day that scares you." --Mary Schmich
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On Wed, 03 Nov 1999 04:29:17 -0800, Ken <tyl### [at] pacbellnet> wrote:
>
>
>Peter Popov wrote:
>
>> These are 2D M-Sets, Ken.
>
>Ok fine ! Last time I try to help someone around here again.
Nah, we won't let you quit, Ken :) . Frankly, we need you. And yeah,
Peter Popov
ICQ: 15002700
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On Wed, 03 Nov 1999 04:15:24 -0800, Ken <tyl### [at] pacbellnet> wrote:
> You might find this interesting. This was just submitted to the links
>collection and looks interesting at least for those interested in fractal
>based programs.
>
>***
>Fractal Programs - A number of Win32 (fractal) programs by Terry Gintz,
>one (FractalZPlot) being especially interesting because of the ability
>to convert the z-buffer information of its 3d-fractal types to Wavefront
>OBJ-format. These in turn can be converted by one of the many conversion
>programs available to povray format for rendering of the 3D fractal object.
>
>http://www-hs.iuta.u-bordeaux.fr/terry/
>
>***
Now this is definitely worth checking out! I will do so as soon as I
get online. Deform_Mesh, here I come!
Peter Popov
ICQ: 15002700
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On 3 Nov 1999 11:00:24 -0500, Nieminen Juha
<war### [at] punarastascstutfi> wrote:
>Peter Popov <pet### [at] usanet> wrote:
>: #declare Rn = (R*R-I*I)+X;
>: #declare In = (2*R*I-J*J)+Y;
>: #declare Jn= (2*J*I+2*J*R)+Z;
>
> Where does this formula come from? Is the formula for Jn just a randomly
>chosen one?
> What's the bailout value?
According to Mark he came up with it. it more of a hack than anything
else, but it sure works darn good. Now here's the snippet of code from
Mark's program that does the iteration:
iter = 0;
r = X; i = Y; j = Z;
while(iter < maxiter && ((r*r)+(i+i)+(j*j)) <= 4)
{
rn = ((r*r)-(i*i))+X;
in = ((2*r*i)-(j*j))+Y;
j = ((2*i*j)+(2*r*j))+Z;
r = rn;
i = in;
iter++;
}
So you see the bailout is 4, as usual (but you can always change it or
leave it to the user)
Peter Popov
ICQ: 15002700
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Nieminen Juha wrote in message <38205c18@news.povray.org>...
>Peter Popov <pet### [at] usanet> wrote:
>: #declare Rn = (R*R-I*I)+X;
>: #declare In = (2*R*I-J*J)+Y;
>: #declare Jn= (2*J*I+2*J*R)+Z;
>
> Where does this formula come from? Is the formula for Jn just a randomly
>chosen one?
> What's the bailout value?
I got J by deciding that J is equal to the square root of -i, and working
from there. The bailout I used was 2 (actually, the formula uses 2^2 as
that is faster than finding a square root), however you may want to use a
higher value.
Mark
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Peter Popov <pet### [at] usanet> wrote:
: while(iter < maxiter && ((r*r)+(i+i)+(j*j)) <= 4)
^
+ ?
--
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/
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