On Wed, 28 Apr 2010 11:54:11 +0200, Dave Blandston <nomail@nomail> wrote:

> "Nekar Xenos" <nek### [at] gmailcom> wrote:
>> Hmm. There are 2 bricks above and 2 bricks below each brick and one on
>> each side = 6 bricks. I'll have to make a larger variety of bricks!
>>
>> -Nekar Xenos-
>
> Not necessarily. See the attached (plagerized) image. With three brick  
> types,
> it's possible that no brick would be directly adjacent to another brick  
> of the
> same type. There's not a whole lot of randomness in this case, though!
>
> Regards,
> Dave Blandston

Oh yes. I didn't think further... :)

-Nekar Xenos-

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