In article <3A53D643.959D0047@online.no>, Tor Olav Kristensen
<tor### [at] onlineno> wrote:
> Maybe it is done like this ?> > x^n = exp(n*ln(x))
Uh, I think "x^n = pow(x, n)" is more likely...
--
Christopher James Huff
Personal: chr### [at] maccom, http://homepage.mac.com/chrishuff/
TAG: chr### [at] tagpovrayorg, http://tag.povray.org/
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