Thomas de Groot wrote:
>>>
>>>isosurface {
>>>  function {y - P(x, 1, 1-z)}
>>
>>What did you expect?  The result of P does not depend on the vertical
>>coordinate.
>>
> 
> Hmm... Consider me as a moron where maths is concerned (very far in the
> past, and not a dayly meal). So, please take me by the hand and explain what
> I should do. After all I used here the function once provided by Mike
> Williams, and I do not pretend to understand exactly what it does...

Well, of course you can do this but when you rotate the function around 
the x or z axis and then evaluate the function in the x-z-plane you will 
just rotate the evaluation plane.  But P is still constant in vertical 
direction.  To get a visible effect from a rotation you will need to 
evaluate the function in 3D: function {y - P(x,y,z)} (but you probably 
will need to adapt the function itself to make it look right).

Christoph

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