"Hugo Asm" <hua### [at] post3teledk> wrote in
news:3eb8c8a3$1@news.povray.org: 

> 
> No insults.  :o)  But how do you compute the almost-even distribution,
> perhaps by subdividing a triangle? If you share your code .. hmm..
> I'll be grateful but it's up to you.. Now you could add some media, or
> maybe you already did.
> 
> Regards,
> Hugo
> 
> 
I just make 2 cycle, the outer scans the "meridians" of the sphere with a 
fixed step, the inner scans the "parallels" (is the right word ?), with a
step that depends on the size of the parallel itself. Here is a snippet
of the code.

#declare fori = object { union {
   #declare zi=0;   
   #while (zi<180)
   
      #declare zrad=sin(zi*pi/180);
      
      #if (zrad=0)
      #declare xstep=360;
      #else
      #declare xstep=360/(30*zrad);   
      #end
      //#declare xstep=int(xstep/5)*5;
      #debug str(xstep,5,2)
      #debug "\n"
      #declare xi=rand(rr)*xstep;                                       
      #while (xi<360)       
         cylinder { <0.9*sin(zi*pi/180),0.9*cos(zi*pi/180),0> 
                    <1.1*sin(zi*pi/180),1.1*cos(zi*pi/180),0>, 
                    0.05 rotate <0,xi,0> }
      #declare xi=xi+xstep;
      #end
   #declare zi=zi+10;
   #end
   } }

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