scott <sco### [at] scottcom> wrote:
> >> I'm no mathematician, but to do that you must make the assumption that
> >> there are an even number of terms in the infinite sum (ie every +1 has a
> >> -1 to pair with it). You could have assumed an odd number of terms and
> >> got a sum of 1 instead.
> >
> >> Writing the sum equals 1 minus the sum seems to avoid the need to make
> >> such an assumption.
> >
> > An infinite sum can't have an "odd" or an "even" number of terms.

> Yes that was my point, "grouping" in any way is invalid because you must 
> make assumptions about the total number of terms, which you can't for an 
> infinite list.

I don't think that's how it works. (If it were, then that original "proof"
would be invalid from the get-go, because it's grouping elements and
summing those groups.)

-- 
                                                          - Warp

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