On 25/08/2014 21:24, Nekar Xenos wrote:
> A) Make a solar system with  binary stars
> 

easy.

> B) Make the binary stars orbit around each other so that the trajectory
> looks like intersecting circles of the same size, yet the stars should
> never collide.
> 

so both stars have nearly the same mass, not a problem. (not a ratio
bigger than 5 ?)


> C) Have a planet for each star without colliding.


Hummm, due to Roche limit, a planet would only survive far away from
both (if it goes between the two and out of it, it's broken in very
small pieces due to the change of the gravity field... or it's not a
planet). So the planet is rather orbiting around the center of mass of
the two stars as one object.

Having two of them is not a problem (Jupiter/Saturn), but they are not
around a star.

A possibility would be to have the planets at the lagrange points.
L1 is hell and there is no place for two there, L2 & L3 are moving too
fast to respect Kepler equation. L4 & L5 (mirrored L4) are on nearly the
same orbit as the second object, so speed is ok to say "I'm orbiting
around..." .

But there is a problem for orbiting around the second star, as L4/L5 are
around the most massive one only... you can of course cheat and assert
the stars have the same masse, but L4/L5 are stable only for mass ratio
above 24.96...

> 
> D) give each planet a moon.

Easy... excepted that each planet still does not exist according to C
unless you are far far away or at L4/L5.

> 
> E) change the size of one moon  to be the same size as it's planet so
> that they become binary planets

So they are even further away from the stars, and they are like pluto
and charon.

Or they are even smaller to fit their orbits safely in L4/L5

stability of L4/L5 is still a problem.

> 
> F) ad a planet that orbits both stars.

I could finally go the easy way for a solar system with enough mass
increase (everywhere) to lighten Jupiter as a star. (but that make the
sun a supermassive star. as Jupiter need a boost to reach 0.07 sun's
mass to burn deuterium, so about a x13 factor)

Stars: sun (x13 mass, candidate to becoming a neutron star one day) &
jupiter as brown dwarf.


> 
> :)
> 


-- 
IQ of crossposters with FU: 100 / (number of groups)
IQ of crossposters without FU: 100 / (1 + number of groups)
IQ of multiposters: 100 / ( (number of groups) * (number of groups))

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