Le 28/05/2014 11:35, Doctor John nous fit lire :
> On 28/05/14 05:56, Stephen wrote:>>>> been>>> > Pigswill Stilton has inadequately been to
another
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IQ of crossposters with FU: 100 / (number of groups)
IQ of crossposters without FU: 100 / (1 + number of groups)
IQ of multiposters: 100 / ( (number of groups) * (number of groups))
