On 8/5/2013 1:44 AM, scott wrote:
>>   vector bbox1 = <pos.x - left, pos.y + boxlen, pos.z - bottom>;
>>   vector bbox2 = <pos.x + right, pos.y + boxlen, pos.z + top>;
>>   vector bbox3 = <pos.x - left, pos.y + boxlen + length, pos.z - bottom>;
>>   vector bbox4 = <pos.x - right, pos.y + boxlen + length, pos.z + top>;
>
> Do you mean "pos.x + right" in that last line?
>
>> integer isInsideBox(vector bbox1, vector bbox2, vector bbox3, vector
>> bbox4)
>> {
>>    vector P = llDectectedPos(0);
>>    vector A1 = <bbox1.x,bbox2.y,bbox1.z>;
>>    vector B1 = <bbox2.x,bbox2.y,bbox1.z>;
>>    vector C1 = <bbox2.x,bbox1.y,bbox1.z>;
>>    vector D1 = <bbox1.x,bbox1.y,bbox1.z>;
>  >    vector A2 = <bbox3.x,bbox4.y,bbox3.z>;
>  >    vector B2 = <bbox4.x,bbox4.y,bbox3.z>;
>  >    vector C2 = <bbox4.x,bbox3.y,bbox3.z>;
>  >    vector D2 = <bbox3.x,bbox3.y,bbox3.z>;
>
> If you substitute in your values for bbox1-4 from above you get the
> following (I left out the pos.x,pos.y,pos.z):
>
> A1 = <-left  , boxlen , -bottom>
> B1 = < right , boxlen , -bottom>
> C1 = < right , boxlen , -bottom>
> D1 = <-left  , boxlen , -bottom>
>
> A2 = <-left  , boxlen+length , -bottom>
> B2 = < right , boxlen+length , -bottom>
> C2 = < right , boxlen+length , -bottom>
> D2 = <-left  , boxlen+length , -bottom>
>
> Is this really what you are expecting?
>
> If you are trying to see if a point is inside a box, then it might be
> simpler to think of the box as being bounded by 6 infinite planes (one
> for each face), then testing which side of each plane the point is on.
> If it's on the "inside" of all 6 planes then it's inside the box.
>
lol What part of, "I know I screwed up the math.", did people miss. ;)

Seriously though, Le_Fogeron says it wouldn't work anyway... :p

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