>   vector bbox1 = <pos.x - left, pos.y + boxlen, pos.z - bottom>;
>   vector bbox2 = <pos.x + right, pos.y + boxlen, pos.z + top>;
>   vector bbox3 = <pos.x - left, pos.y + boxlen + length, pos.z - bottom>;
>   vector bbox4 = <pos.x - right, pos.y + boxlen + length, pos.z + top>;

Do you mean "pos.x + right" in that last line?

> integer isInsideBox(vector bbox1, vector bbox2, vector bbox3, vector bbox4)
> {
>    vector P = llDectectedPos(0);
>    vector A1 = <bbox1.x,bbox2.y,bbox1.z>;
>    vector B1 = <bbox2.x,bbox2.y,bbox1.z>;
>    vector C1 = <bbox2.x,bbox1.y,bbox1.z>;
>    vector D1 = <bbox1.x,bbox1.y,bbox1.z>;
 >    vector A2 = <bbox3.x,bbox4.y,bbox3.z>;
 >    vector B2 = <bbox4.x,bbox4.y,bbox3.z>;
 >    vector C2 = <bbox4.x,bbox3.y,bbox3.z>;
 >    vector D2 = <bbox3.x,bbox3.y,bbox3.z>;

If you substitute in your values for bbox1-4 from above you get the 
following (I left out the pos.x,pos.y,pos.z):

A1 = <-left  , boxlen , -bottom>
B1 = < right , boxlen , -bottom>
C1 = < right , boxlen , -bottom>
D1 = <-left  , boxlen , -bottom>

A2 = <-left  , boxlen+length , -bottom>
B2 = < right , boxlen+length , -bottom>
C2 = < right , boxlen+length , -bottom>
D2 = <-left  , boxlen+length , -bottom>

Is this really what you are expecting?

If you are trying to see if a point is inside a box, then it might be 
simpler to think of the box as being bounded by 6 infinite planes (one 
for each face), then testing which side of each plane the point is on. 
If it's on the "inside" of all 6 planes then it's inside the box.

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