Le 13/11/2012 07:04, Stephen a écrit :
> 
> I did some quick calculations and knowing that the centripetal force is
> equal to minus the angular velocity squared times the radius times the
> mass (F = -W^2*r*m).
> If the torus was revolving around its centre once in 24 hours. On the
> inner surface the force would be about 0.508g and on the outside surface
> 0.529g. If the period was 12 hours the forces would be 2.03g and 2.116g
> respectively. Note the sleight of hand going from force to acceleration ;-)


There is more than just a delta in the centripetal force. (on the outer
circle, it is opposite direction of gravity (like on earth); on the
inner circle, it should be the same direction as local gravity (but the
local gravity is diminished due to the point being between "two massive
parts"

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