Le 26/07/2012 13:51, Invisible nous fit lire :
> Now I can't help but wonder... Is this a coincidence? Or some deep
> fundamental result? Is there some way of writing a solution to an
> equation like
> 
>   f''(t) = k f(t)
> 
> such that you get exp() or sin() depending on the sign of k?

what about f''(t) = exp(abs(sqrt(k)).t) ?

when k = -1, abs(sqrt(k)) is i
when k = 1, it's 1.

Post a reply to this message