>> That's great. Now tell me, is the set of all sets that list themselves
>> listed in itself?
>
> I assume by "list" you mean "contain"?

Yes.

> If so, then I think the answer is no.

And I think the answer is "Russell's paradox".

Interestingly, in Portal 2 GLaDDOS poses nearly the exact same question 
to Wheatly, who also responds with "false".

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