On 4/20/2012 0:55, Invisible wrote:
>>>>> while (x[i] = y[i--]) ;
>>>>
>>>>> is perfectly valid. You sick, sick people.
>>>>
>>>> I think that's Undefined Behavior because the same variable is being
>>>> modified and referenced more than once in the same expression.
>>>>
>>>
>>> Nothing undefined here.
>>
>> Does it compare x[i] to y[i] or to y[i-1]? Why do you answer that way?
>
> Last time I checked, the /comparison/ operator is ==.
>
> The = operator performs *assignment*. :-P

Yah yah. Still missing the point. It's still undefined, whether it's an 
assignment or a comparison.

-- 
Darren New, San Diego CA, USA (PST)
   "Oh no! We're out of code juice!"
   "Don't panic. There's beans and filters
    in the cabinet."

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