On 4/20/2012 0:20, Le_Forgeron wrote:
> Le 20/04/2012 03:56, Darren New a écrit :
>> On 4/19/2012 18:38, Alain wrote:
>>> Le 2012/04/17 09:40, Warp a écrit :
>>>
>>>>> is a perfectly valid statement in C++. On the other hand, it also
>>>>> means that
>>>>
>>>>> while (x[i] = y[i--]) ;
>>>>
>>>>> is perfectly valid. You sick, sick people.
>>>>
>>>> I think that's Undefined Behavior because the same variable is being

>>>> modified and referenced more than once in the same expression.
>>>>
>>>
>>> Nothing undefined here.
>>
>> Does it compare x[i] to y[i] or to y[i-1]?  Why do you answer that way
?
>>
> You missed the point: let's name k the initial value of i;

I don't think I missed the point. I just got the possible answers wrong. 
The 
*point* was that there *were* multiple possible answers. :-)

-- 
Darren New, San Diego CA, USA (PST)
   "Oh no! We're out of code juice!"
   "Don't panic. There's beans and filters
    in the cabinet."

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