On 4/19/2012 18:38, Alain wrote:
> Le 2012/04/17 09:40, Warp a écrit :
>
>>> is a perfectly valid statement in C++. On the other hand, it also mea
ns that
>>
>>> while (x[i] = y[i--]) ;
>>
>>> is perfectly valid. You sick, sick people.
>>
>> I think that's Undefined Behavior because the same variable is being
>> modified and referenced more than once in the same expression.
>>
>
> Nothing undefined here.

Does it compare x[i] to y[i] or to y[i-1]?  Why do you answer that way?

-- 
Darren New, San Diego CA, USA (PST)
   "Oh no! We're out of code juice!"
   "Don't panic. There's beans and filters
    in the cabinet."

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