Fredrik Eriksson <fe79}--at--{yahoo}--dot--{com> wrote:
> 'fold' (should probably be 'foldl1') is just a library function, not a  
> language primitive. The corresponding C++ library function is  
> 'std::accumulate'.

>    std::accumulate( my_list.begin(), my_list.end(), 0 );

  Which got me thinking: Does foldl1 in haskell work for data containers
other than lists? What if you want to apply it to only a sub-range inside
the data container rather than to the entire container? (Can you do it
without copying the sub-range to a separate container?)

-- 
                                                          - Warp

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