High!

Xavier M. schrieb:

> The equation of your ellipsoid is:
> (x/0.115)^2 + (y/0.108)^2 + (z/0.138)^2 - 1 = 0
> The cut surface z==-0.097 is an ellipse, with equation:
> (x/0.115)^2 + (y/0.108)^2 + (0.097 /0.138)^2 - 1 = 0
> the width at y=0 is given by:
> (x/0.115)^2 + (0.097 /0.138)^2 - 1 = 0
> <=> |x| = 0.115 * sqrt ( 1 - (0.097 /0.138)^2)
> so width = 2 * 0.115 * sqrt ( 1 - (0.097 /0.138)^2)

Meanwhile, I found out a different solution:
as the length of the secant of a circle or ellipse decreases with 
increasing distance to its center point proportionally with the cosine 
of the arcus-sine of distance/radius, the searched length here is 
0.115*2*cos(asin(0.097/0.138)) = 0.163596726 !

But nevertheless, thank you!

See you in Khyberspace!

Yadgar

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