Slime schrieb:
>>This worked nicely, thank you. A small tweak in the accuracy and
>>max_gradient and I have this.
> 
> 
> Nice. You might even want to use this version:
> 
> #local smoothfunc = function(x) {x*x*x*(10+x*(6*x-15))}
> 
> Which also matches second derivatives, and will make the transition from
> straight to curved even more invisible.
> 

Nice, how did you calculate it?
Once I made some differential equations
for this problem and solved them.
It was a bit dirty and some paper sheets got lost.
If I remember right the differential equations
for a smooth transition from 0 to 1 were:

f(0) = 0
f(1) = 1

df(0)/dx = 0   # match in first derivative
df(1)/dx = 0

d^2f(0)/dx = 0 # match in second derivative
d^2f(1)/dx = 0

An approximation method aka Taylor or
something which could be used to get a match
in even higher derivatives would be nicer
but when I got f(x) for the second derivative
I forgot thinking about it further.

Sebastian

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