POV-Ray : Newsgroups : povray.general : Some aid in physics required... : Re: Some aid in physics required... Server Time
2 Nov 2024 13:17:36 EDT (-0400)
  Re: Some aid in physics required...  
From: Jellby
Date: 23 Feb 2004 12:33:59
Message: <403a3986@news.povray.org>
Among other things, Tim Nikias v2.0 wrote:

>> Ignoring friction and rotational energy, you'd simply be checking that
>> your potential energy matches your kinetic energy, wouldn't you? The
>> formulae for both are pretty straightforward.
> 
> Ehm, yeah, sure... Point is: I can't find those formulae. That aside, I
> just want the velocity approach, not energies etc, cause I don't know
> anything else of that particle beside it's velocity. Might be that I'm
> talking BS because I don't know which formulae you're talking about, but,
> for example, I've got a few formulae like "Height after object is thrown
> with that slope and that velocity with earth's gravity". What I want is
> something along the lines of "Velocity after object is rolled up/down a
> slope with that angle, velocity and gravity".

Kinetic energy: 1/2 * m * v^2
Potential energy: g * m * h

Total energy must be constant.

If the particle has velocity v1 at height h1, then at height h2 it should 
have:

1/2*m*(v1)^2 + g*m*(h1) = 1/2*m*(v2)^2 + g*m*(h2)
1/2*m*(v2)^2 = 1/2*m*(v1)^2 - g*m*(h2-h1)
(v2)^2 = (v1)^2 - 2*g*(h2-h1)
v2 = sqrt[ (v1)^2 - 2*g*(h2-h1) ]

-- 
light_source{9+9*x,1}camera{orthographic look_at(1-y)/4angle 30location
9/4-z*4}light_source{-9*z,1}union{box{.9-z.1+x clipped_by{plane{2+y-4*x
0}}}box{z-y-.1.1+z}box{-.1.1+x}box{.1z-.1}pigment{rgb<.8.2,1>}}//Jellby


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