Christoph Hormann wrote:
No, you don't have to modify the function as ABX already pointed out:
> > #declare fn_Shape = function { ... }> > #declare fn_Iso = IC_Displace (fn_Shape)> > isosurface {> function { fn_Iso(x,y,z) }> ...> }>
And this our point of contention. I say
the isosurface here is the result of fn_Iso,
and not a displacement of fn_Shape and you
disagree.
Dave
