> Tor said in another thread that normalizing sums of
> the non-normalized vcross of each triangle would
> give the correct weighted normal, and he was correct

Does this mean, I'm now using weighted normals and not just averaged ones?
I actually didn't know.  It's some time ago I decided to skip vnormalize
until the very end as this seemed logical. But I don't always know what I'm
doing.

> I am pretty sure that vcross(V2-V1,V1-V3) gives
> a more accurate result

I'll try, thanks for the tip!

Regards
Hugo

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