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> From: "R. Suzuki"
>The max() and evaluate are tips for faster rendering.
>You don't need them if the rendering speed is acceptable for you.
>Without the max(), the maximum gradient of the function
>is extremely high. It slows down rendering.
Ok.
>>I thought that the surface would be drawn where the function becomes
>>zero, but then if 6 - f_bfield() is zero then f_bfield() - 6 should be
>>zero too! So I don't understand why this change makes such a
>>huge difference.
>
>Because the isosurface is not a surface object---it is a solid object
>by default. If you want to see only the surface of your original
>function, you should add 'open' keyword. (see POV-Help 6.5.4.1)
Ah, yes! my problem was that the bfield function gets *less* as you
go away from the origin - the opposite of "simpler" functions
what I'm used to, where the function gets bigger as x, y and z
increase.
So my function was, essentially, inside-out!
POV-Ray is counting all the values which are less than the threshold
as "inside", and those greater as "outside" this solid object.
With "6 - f_bfield()" the negative bits (ie less than threshold, with
threshold == 0) are all where they should be (between the origin and
the surface) and with "f_bfield - 6" they are all where they
*shouldn't* be - everywhere "outside" the surface, using "outside"
to mean the side of the surface that the camera is on, rather than
what POV-Ray means by it. So the change serves to align POV-Ray's
notion of "inside" and "outside" (in this case) with my simple
intuitive one.
I guess when I was rendering with "f_bfield() - 6" there was a
donut-shaped hole right in the middle of my huge red cube, which I
would have seen if I'd chopped it open ;-)
This makes sense. As someone once said: "Now I can go on!"
>>> evaluate 10,1.1,0.99
>Well, this is the dynamic max_gradient estimation technique and
>it has not been documented yet.
Right. Having re-read the isosurface part of the beta documentation,
it seems to be saying "don't worry about it, just put these magic
numbers in your script" ;-)
> See my messages
>http://news.povray.org/3bd7f6e8$1@news.povray.org
>http://news.povray.org/3be10cf9@news.povray.org
I'll have a look. Thanks again.
- Pete.
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