POV-Ray : Newsgroups : povray.binaries.animations : Kochcurve3D(?) : Kochcurve3D(?) Server Time
2 Nov 2024 15:27:39 EDT (-0400)
  Kochcurve3D(?)  
From: Jan Walzer
Date: 2 Dec 2001 10:15:23
Message: <3c0a458b@news.povray.org>
Anders Haglund did some days ago something with a regular kochcurve in POV,
and as he said, he wanted to do it in 3d, but didn't know how ...

I got the idea, to apply the algorithm to a regular triangle, dividing it
into 6 triangles, greating one peak ...

it looked nice, so I did it with a tetraedron ...

the shape is no longer something lige a snowflake, but it converges against
the shape of a cube ...

it's a pity, that my simplest math left me, when I tried, to make the sides
of the trianles equal ...
Thats the reason(I think), why it looks like a distorted cube, and why it
doesn't loop correctly...

somewhere there must be some mistake...
Can anyone spot, where I got wrong ?

1)
the points of a regular tetraedron can have the following coordinates

#declare h=sqrt(3/4);
#declare p1=<   0,-1/3*h, 2/3>;
#declare p2=< 1/2,-1/3*h,-1/3>;
#declare p3=<-1/2,-1/3*h,-1/3>;
#declare p4=<   0, 2/3*h,   0>;

2)
to calculate the top of the new pyramid that I create on a triangle,
I use the following:
(I assume, if I'd use a "real" regular triangle, it could be simplified)

p1,p2,p3 are now the points of the triangle, to be subdivided...
p4 is the new point at the top of the pyramid..

#local a=vlength(p2-p1);
#local b=vlength(p3-p2);
#local c=vlength(p1-p3);
#local n=vnormalize(vcross(p2-p1,p3-p1))*sqrt(a^2-(sqrt(b^2-(c/2)^2)/3)^2);

#local p4=(p1+p2+p3)/3+n/3;

3)
if I rotate a regular tetraedron, resting on the floor, by

rotate <0,120*clock,360*clock>

Shouldn't it perfectly loop ?

Can anyone spot the mistakes I did ? ...

Any other comments ?


--
Jan Walzer <jan### [at] lzernet>


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Attachments:
Download 'koch3.avi.dat' (495 KB)

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