POV-Ray : Newsgroups : povray.binaries.images : Re: Color question : Re: Color question Server Time
17 Aug 2024 06:17:52 EDT (-0400)
  Re: Color question  
From: bob h
Date: 25 Nov 2001 04:57:29
Message: <3c00c089@news.povray.org>
Well, my point about this is how rgb ought to prevent rgbft from being used.
I can see how your logic would work were there no "rgb" but its presence
should mean anything following it is a 3 float vector.  And even though my
example had all 5 it still does the promotion to 5 when all are only 3.  The
filter and transmit keywords should be what is needed to get back to all 5
again from that rgb color value.

That's my reasoning anyway.

What you've said is essentially that a <red,green,blue,filter,transmit> is
omnipresent regardless of choosing to use rgb alone.  Again, I can see that
being likely once using the 5 floats vector afterward but they are set to
zero.  1-0=1 but only if rgb 1 = rgbft 1.

Hope I'm not losing you, Mike Williams had said the same thing really.

--
text{ttf"arial","bob h",.1,0pigment{rgb 9}translate<-1,-.2,3>}

"Marc-Hendrik Bremer" <Mar### [at] t-onlinede> wrote in message
news:3c00ba66$1@news.povray.org...
>
> bob h schrieb in Nachricht <3c005a27@news.povray.org>...
>
> >rgb 1 - <1,1,1,0,0>*<.25,.25,.25,0,0> = <.75,.75,.75,1,1>
>
>
> Why not? As the multiplication is prior to the subtraction you get
> <1,1,1,1,1> - <0.25,0.25,0.25,0,0> which gives you the result you
mentioned.
>
> Marc-Hendrik
>


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