Margus Ramst wrote:
> When I tried something similar, the only way I could figure out how to
> split the cube was into 5 tetrahedrons (4 with faces coinciding with
> cube faces, 1 "in the middle"); how did you distribute the 6 ones?

One way is to start with a diagonal of the cube as an edge common to all
six.  Is there another?

-- 
Anton Sherwood  --  br0### [at] p0b0xcom  --  http://ogre.nu/

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