Chris Huff wrote:
> > In article <3A53D643.959D0047@online.no>, Tor Olav Kristensen> <tor### [at] onlineno> wrote:> > > Maybe it is done like this ?> >> > x^n = exp(n*ln(x))> > Uh, I think "x^n = pow(x, n)" is more likely...
Yes, but do you know how this is actually computed ?
Regards,
Tor Olav
--
mailto:tor### [at] hotmailcom
http://www.crosswinds.net/~tok/tokrays.html